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zloy xaker [14]
2 years ago
6

Find the area of a circle with radius, r = 6.02m. Give your answer rounded to 2 DP.

Mathematics
1 answer:
lozanna [386]2 years ago
4 0

Answer:

113.85

Step-by-step explanation:

Area = (pi)r^2

(6.02)^2 times pi

36.2404pi

113.8525

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What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
3 years ago
You and a friend went to the movies. You decide to get some snacks. You got 2 boxes of candy that cost $3.49 for each box. You a
Dima020 [189]

Answer:

You and your friend spent $17.30 together

Step-by-step explanation:

3.49 x 2 = 6.98

6.98 + 4.82 = 11.8

11.8 + 5.50 = 17.3

3 0
3 years ago
I put a picture
Ksivusya [100]

Answer:

Yes, an arrow can be drawn from 10.3 so the relation is a function.

Step-by-step explanation:

Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.

The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.

In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.

However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.

3 0
3 years ago
A piano, which normally sells for $800, is marked
belka [17]

Answer

700 is 87.5% of 800

Step-by-step explanation:

8 0
3 years ago
ASAP what is the value of k?<br> -3(k+7) - 5k+4=23
Maru [420]

Answer:

k=−5

Step-by-step explanation:

−3(k+7)−5k+4=23

(−3)(k)+(−3)(7)+−5k+4=23(Distribute)

−3k+−21+−5k+4=23

(−3k+−5k)+(−21+4)=23(Combine Like Terms)

−8k+−17=23

−8k−17=23

Step 2: Add 17 to both sides.

−8k−17+17=23+17

−8k=40

Step 3: Divide both sides by -8.

−8k

−8

=

40

−8

k=−5

Answer:

k=−5

 

6 0
3 years ago
Read 2 more answers
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