Answer:
see explaination
Explanation:
//selective dev elements by id name
var gradeA = document.querySelector("#GradeA");
var passing = document.querySelector("#Passing");
var learning = document.querySelector("#Learning");
//function showGrades
function showGrades() {
var arr = [];
//converting string to int and inserting into array
arr[0] = parseInt(gradeA.textContent);
arr[1] = parseInt(passing.textContent);
arr[2] = parseInt(learning.textContent);
//creating json blob
var blob = new Blob(new Array(arr), {type:"text/json"});
return blob;
}
Answer:
"ArithmeticException" is the correct answer for the above question.
Explanation:
Missing Information : The above question does not hold that "what is the output of the program".
- The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.
- The method function holds one run time exception which is 1/0 which is an arithmetic exception.
- It can be handle by the help of an arithmetic class object which is defined in the first catch block.
- Hence the print function of this catch is executed and prints "ArithmeticException".
Answer:
12. for (i = 0 ; i < testGrades.length ; i+=1 ){
13. if (testGrades[i] > 100){
14. sumExtra = sumExtra + testGrades[i] - 100;}
15. }
Explanation:
We first iterate through the entire testGrades array. For each test score that is in testGrades ( that is testGrades[i] ), we see whether or not the test grade is above 100 (See line 12) . If test grade is greater than 100, this means we have extra credit. We simply subtract 100 from the test grade, add it with the previous value of sumExtra and store the value back in sumExtra(see line 14). Once i is greater than the length of the test grades, the loop is exited. We can now print sumExtra to obtain the result.
Answer:
21
Explanation:
The values of c that make it into the loop are 1, 4, 7.
The values that are added to sum are 3 higher, i.e., 4,7 and 10.
The sum of those is 21.
p.s. why did you not run the program yourself?
