All categories

3 years ago

Help me ASAPthank you

Mathematics

1 answer:

Serga [27]3 years ago

8 0

Answer:

<h3>a.China - 52</h3>

<h3>b.Malaysia - 76</h3>

<h3>c.Singapore - 57</h3>

<h3>Will You Be My Friend?</h3>

<h3>Plz mark Me brainliest Dear☺☺</h3>

You might be interested in

Two towns are 80km apart. Sylvia wants to drive from one town to the other in exactly one hour. For the first 30minutes she driv

Varvara68 [4.7K]

Answer:

100 km/hr

Step-by-step explanation:

First Leg:

Speed = 60 km/h

Time = 30 min = 0.5 h

1st leg distance = speed x time = 60 km/hr x 0.5hr = 30 km

Second Leg:

Distance remaining = 80 km - 30 km = 50 km

Time = 30 min = 0.5 h

speed = distance / time = 50 / 0.5 = 100 km/hr

5 0

3 years ago

Why do the inequality signs stay the same in the last two steps of exercise 1

MrRissso [65]

The only reason an inequality would change would be because a number is divided or multiplied by a negative number. So if it stayed the same, then it would be because there was no division or multiplication by a negative number. Hope I helped :)

7 0

3 years ago

Read 2 more answers

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Mr. Theorem writes the expressions Six to the second power divided by 2m on the board.what is the value of this expression when

Ulleksa [173]

6, if m=3 then it must be 36/6 which is equal to 6

4 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

Ronch [10]

The formulas for conditional probability are:
$P(A\cap B')=P(A)\cdot P(B'|A)$
$P(A\cap B')=P(B')\cdot P(A|B')$ .
Since $P(A\cap B')= \frac{1}{6}$ and $p(B')= \frac{7}{18}$ , you have the equation $\frac{1}{6} = \frac{7}{18} \cdot P(A|B')$ .
Therefore, $P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}$ .
Answer: The correct choice is D.

8 0

3 years ago

Help me ASAPthank you​

Help me ASAPthank you