Is 5/6 closer to 0,1/2,or 1

Lady bird [3.3K]

2503 is the answer, you can use a calculator to find this by simply plugging it in or use the long division method

7 0

3 years ago

The base of a triangular prism is a right triangle with a base of 5 inches, a height of 12 inches, and a third side length of 13

myrzilka [38]

Answer:

690 sq in

Step-by-step explanation:

SA = LA + 2B where LA is the lateral area and B is the area of the base

The triangular base has an area of

B = 1/2bh 1/2(5)(12) = 30

LA = ph where p is the perimeter of the base and h is the height of the prism

LA = (12 + 5 + 13)(21) = 30(21) = 630

SA = 630 + 2(30) = 630 + 60 = 690 sq in

3 0

3 years ago

Mrs. Donelly drew the triangle above on the chalkboard and asked her students to write down possible side lengths for a, b, and

GenaCL600 [577]

Answer:

a=2;b=4;c=6.

Louis wrote the correct answer.

4 0

3 years ago

Need help as soon as possible! What is the value of g(3)? 2 3 9 14

Alex777 [14]

g(x) is a piecewise function in such a way that it changes how it's defined based on what x happens to be. There are three cases

Case A: g(x) = x-1 but only if $-2 \le x < -1$ (x is between -2 and -1; including -2 but excluding -1)

Case B: g(x) = 2x+3 but only when $-1 \le x < 3$ (x is between -1 and 3; including -1 but excluding 3)

Case C: g(x) = 6-x but only when $x \ge 3$

The input is x = 3 since we want to find the value of g(3). So we look at the 3 cases above (A,B,C) and determine that we use case C. Why? Because x = 3 makes $x \ge 3$ true. Put another way, x = 3 is in the interval [3, infinty). So we'll use g(x) = 6-x to find that...

g(x) = 6-x

g(3) = 6-3

g(3) = 3

Answer: 3

5 0

3 years ago

Write the equation of each line using the given information.

Leni [432]

a) x – 2y + 6 = 0 b) x + y = 1 c) y = 1 d) y = -3x + 8

<h3>Solution:</h3>

a. The points (-4,1) and (2,4) both lie on the line

The general line equation on which (a, b) and (c, d) lies is:

$y-\mathrm{b}=\frac{d-b}{c-a}(x - a)$

Here the given points are (a, b) = (-4, 1) and (c, d) = (2, 4)

Thus the required equation is:

$y-1=\frac{4-1}{2-(-4)}(x-(-4))$

On solving we get,

$\begin{array}{l}{\rightarrow y-1=\frac{3}{2+4}(x+4)} \\\\ {\rightarrow y-1=\frac{3}{6}(x+4)} \\\\ {\rightarrow 2(y-1)=1(x+4)} \\\\ {\rightarrow 2 y-2=x+4} \\\\ {\rightarrow x-2 y+6=0}\end{array}$

b.) m= -1 and the point (2, -1) lies on the line

The equation of line in point slope form is y – b = m(x – a)

where m is slope and (a, b) is a point on it

Here m = -1 and (a, b) = (2, -1)

Thus the required equation is:

y – (-1) = -1(x - 2)

y + 1 = -x + 2

y = -x + 2 -1

y = -x + 1

c. )It has the same slope as y = 5 and passes through (1, 1)

our line has same slope with y = 5, then our equation would be y = k and it passes through (x, y) = (1, 1) so, then by substitution

1 = k

k =1

Then our equation will be y = k

y = 1

d. ) m= -3 and it has a y-intercept of (0, 8)

line equation in slope intercept form is y = mx + b where m is slope and b is y – intercept.

Then, our equation will be y = -3x + 8

We took y- intercept = 8 as it is the value of y when x = 0

6 0

3 years ago