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3 years ago

HELP LAST ATTEMPT ( get marked brainliest show work

Mathematics

2 answers:

ziro4ka [17]3 years ago

7 0

Answer:

144

Step-by-step explanation:

48 ÷ 4 (which is how many sides a square has) is 12

So 12x12 because l×w (length and width) and all sides of a square are equal

So the answer would be 144

ZanzabumX [31]3 years ago

5 0

<h3>Question:</h3>

The perimeter of a square is 48 inches. What is the area, in square inches, of the square?

<h3>Statement:</h3>

The perimeter of a square is 48 inches.

<h3>Solution:</h3>

We know, perimeter of a square = 4 × length of a side of a square.
So, the length of a side of a square = Perimeter of the square ÷ 4
Therefore, the length of the given square

= 48 inches ÷ 4

= 12 inches

Now, area of a square = square of the length of a side of the square
Therefore, the area of the given square

= (12 inches)^2

= (12×12) square inches

= 132 square inches

<h3>Answer:</h3>

The area of the square is 132 square inches.

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Answer:

n=206

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.09$ , we can use as prior estimate of p 0.5, since we don't have any other info provided, and we are interested in order to find the value of n, if we solve n from equation (a) we got: