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Gnesinka [82]
3 years ago
10

How much is 4 raised to 4?​

Mathematics
2 answers:
Over [174]3 years ago
5 0

Answer:

4 raised to 4 is 256

Step-by-step explanation:

Wittaler [7]3 years ago
5 0

Answer: 256

Step-by-step explanation:

Remember: to calculate by elevated you have to calculate the same number the same number of times. For example: 4 raised by 4 is: 4 x 4 x 4 x 4 and that multiplication results in: 256. I hope and it has helped you ;)

You might be interested in
The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?
Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

7 0
3 years ago
Simplify the following​
den301095 [7]

Answer:

1) 11\sqrt{3}

2) 2\sqrt{2}

3) 20\sqrt{3}  + 15\sqrt{2}

4) 53 + 12\sqrt{10}

5) -2

6) 7\sqrt{2}  - 5\sqrt{3}

Step-by-step explanation:

1) 2\sqrt{12} + 3\sqrt{48} - \sqrt{75}

=(2 × 2\sqrt{3} )+ (3 × 4\sqrt{3}) - 5\sqrt{3}

= 4\sqrt{3} + 12\sqrt{3} - 5\sqrt{3}

= 11\sqrt{3}

2) 4\sqrt{8} -2\sqrt{98} + \sqrt{128}

= (4 × 2\sqrt{2}) - (2 × 7\sqrt{2}) + 8\sqrt{2}

= 8\sqrt{2} - 14\sqrt{2} +8\sqrt{2}

= 2\sqrt{2}

3) 5\sqrt{12\\} - 3\sqrt{18} + 4 \sqrt{72}  +2\sqrt{75}

= 5× 2\sqrt{3} - 3×3\sqrt{2} + 4×6\sqrt{2} + 2×5\sqrt{3}

= 10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}

= 20\sqrt{3}  + 15\sqrt{2}

4) (2\sqrt{2}  + 3\sqrt{5} )^{2}

= 8 + 12\sqrt{10} + 45

= 53 + 12\sqrt{10}

5) (1+\sqrt{3} ) (1-\sqrt{3} )

= 1 - 3

= -2

6) (2\sqrt{6} -1) (\sqrt{3} -\sqrt{2}  )

= 2\sqrt{18}-2\sqrt{12}  -\sqrt{3}  +\sqrt{2}

= 2×3\sqrt{2} - 2×2\sqrt{3} - \sqrt{3} + \sqrt{2}

= 6\sqrt{2}  - 4\sqrt{3} -\sqrt{3} +\sqrt{2}

= 7\sqrt{2}  - 5\sqrt{3}

Hope the working out is clear and will help you. :)

5 0
3 years ago
Read 2 more answers
Write a trinomial of degree 35
Virty [35]
We know that
<span>Trinomial of degree 35  means a polynomial
that
a) Having three terms
b) highest degree is 35

examples
x</span>^35+x³+3
x^35+2x-8
x^35+x²+2
etc
8 0
3 years ago
You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just
Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C  = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is \frac{C}{2\pi}

So the area of the square is

A_S = \frac{S^2}{4^2} = \frac{S^2}{16}

A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}

Therefore the total area is

A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}

We can substitute 100 - C for S

A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}

A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})

To find the maximum and minimum of this, we can take the first derivative and set that to 0

A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0

C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5

C \approx 44 cm

If we take the 2nd derivative:

A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2

if S = 100 then A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0
3 years ago
Complete the square to determine the minimum or maximum value of the function defined by the expression.
Alekssandra [29.7K]

The minimum value at -1 ⇒ D

Step-by-step explanation:

The completing square form of ax² + bx + c is a(x - h)² + k, where

  • h=\frac{-b}{2a}
  • k is the value of of the expression when x = h
  • k is minimum if a > 0 and maximum if a < 0

∵ The expression is x² + 4x + 3

∴ a = 1 , b = 4 , c = 3

- Use the rule above to find h

∵ h=\frac{-4}{2(1)}

∴ h = -2

- To find k substitute x by the value of h

∵ k = (-2)² + 4(-2) + 3 = 4 - 8 + 3

∴ k = -1

- Substitute h and k in the form of the completing square

∵ a(x - h)² + k = 1(x - -2)² + (-1)

∴ a(x - h)² + k = (x + 2)² - 1

∴ x² + 4x + 3 = (x + 2)² - 1

∵ The completing square is (x + 2)² - 1

∵ a = 1 ⇒ greater than zero

∴ The value is minimum

- The minimum value is the value of k

∵ k = -1

∴ The minimum value of the function is -1

The minimum value at -1

Learn more:

You can learn more about the quadratic function in brainly.com/question/9390381

#LearnwithBrainly

3 0
3 years ago
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