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neonofarm [45]
2 years ago
15

Choose SSS, SAS, or neither to compare

Mathematics
1 answer:
Oliga [24]2 years ago
8 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

According to above figure, we can conclude that :

  • The given triangles are congruent by SSS criteria.
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What is the number 21.0384 rounded to the nearest hundredth?
Anton [14]

Answer:

21.04

Step-by-step explanation:

the 8 is closest to 10 so that would make the 3 a 4.

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3 years ago
Solve the following problems using 5-D process part 2
svet-max [94.6K]

The two problems are almost identical: you have to set up a system, and then solve it.

In the first case, let g and b be, respectively, the number of girls and boys.

We know that g=2b+4 (the number of girls in the Spanish Club is four more than twice the number of boys). Also, we know that g+b=61 (there are 61 students in total).

So, we have the system

\begin{cases}g=2b+4\\g+b=61\end{cases}

We can use the first equation to substitute in the second

g+b=61 \iff (2b+4)+b=61 \iff 3b+4=61 \iff 3b=57 \iff b=19

And then solve for g:

g=2b+4=2\cdot 19+4=38+4=42

For the second problem, let c and j be the number of pins knocked down by, respectively, Carrie and John. Just like before, we have the system

\begin{cases}c=j+12\\c+j=230\end{cases}

And you can solve it in the very same way we solved the previous one.

5 0
3 years ago
What is the solution to this equation 2+x=7/8x-15
Svetach [21]

Answer:

x= -136

Step-by-step explanation:

6 0
3 years ago
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I am an even number i am less than 100,the sum of my digits is 15, i am multiple of 12
Yakvenalex [24]

Answer:

96

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7 0
3 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
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