3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! (5x 2 y 4 ) 3 The 2,4, and 3 are Exponents

Mathematics

2 answers:

NeTakaya3 years ago

8 0

Answer:

X and y are the variables

Isnt?

frosja888 [35]3 years ago

6 0

Answer:

wait is the problem your asking (5x^(2)y^(4))^(3)? (^ means exponent)

if it is then the answer is 125x 6 y 12

(6y12 exponents)

Step-by-step explanation:

You might be interested in

PLEASE HELP MAX POINTS

erma4kov [3.2K]

Best Answer: <span> 1.)
x^2 + y^2 = 30^2 since the radius is 30 ft
x^2 + y^2 = 900

2.)
Solving for y
y = √(900 - x^2) </span>

7 0

3 years ago

Read 2 more answers

Simplify(-4.5(-6(5.4

kherson [118]

If this is all multiplication
145.8

8 0

3 years ago

Read 2 more answers

-2 ≤2x-4 <4 solve inequality

Korolek [52]

-8 < 4

hope it helps

4 0

1 year ago

Read 2 more answers

Divide £ 45 among 3 person so that their share are in the ratio 4:5:6

NISA [10]

Answer:

12, 15, 18

Step-by-step explanation:

4x+5x+6x=45

15x=45

x=3

4x=12, 5x=15, 6x= 18

6 0

3 years ago

Describe the set of points z in the complex plane that satisfy the given equation; |z-2|=Re(z).

OLEGan [10]

Answer:

Parabola with vertex at point (1,0) that goes to the right (see attached diagram).

Step-by-step explanation:

Let the complex number z be

$z=x+iy,$

then

$z-2=x+iy-2=(x-2)+iy\\ \\Re\ (z-2)=x-2\\ \\Im\ (z-2)=y\\ \\|z-2|=\sqrt{Re^2\ (z-2)+Im^2\ (z-2)}=\sqrt{(x-2)^2+y^2}$

and

$Re\ z=x$

Thus,

$\sqrt{(x-2)^2+y^2}=x$

Square it:

$(x-2)^2+y^2=x^2\\ \\x^2-4x+4+y^2=x^2\\ \\-4x+4+y^2=0\\ \\y^2=4x-4\\ \\y^2=4(x-1)$

This is the equation of parabola with vertex at point (1,0) that goes to the right.

3 0

3 years ago