c = cost per pound of chocolate chips
w = cost per pound of walnuts.
![\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B3%20lbs%20of%20%22c%22%7D%7D%7B3c%7D%2B%5Cstackrel%7B%5Ctextit%7B5%20lbs%20of%20%22w%22%7D%7D%7B5w%7D~~%3D~~%5Cstackrel%7B%5Ctextit%7Bcosts%7D%7D%7B15%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B12%20lbs%20of%20%22c%22%7D%7D%7B12c%7D%2B%5Cstackrel%7B%5Ctextit%7B2%20lbs%20of%20%22w%22%7D%7D%7B2w%7D~~%3D~~%5Cstackrel%7B%5Ctextit%7Bcosts%7D%7D%7B33%7D%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimpliedby%20%5Ctextit%7Blet%27s%20use%20elimination%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllccccccl%7D%203c%2B5w%3D15%26%5Ctimes%20%28-4%29%5Cimplies%20%26-12c%26%2B%26-20w%26%3D%26-60%5C%5C%2012c%2B2w%3D33%26%2612c%26%2B%262w%26%3D%2633%5C%5C%20%5Ccline%7B3-7%7D%5C%5C%20%26%260%26%26-18w%26%3D%26-27%20%5Cend%7Barray%7D)
I'm guessing these are regular polygons so... here goes.... 11. angle 1 is (8-2)*180= 1080 then divide that by 8 (how many angles there are ) to get 135. angle 2 is 360/8 (the sum of the exterior angle is always 360) which is 45 and multiply it by 2 (because the two polygons are stuck together) to get 90.
12. it says 2 squares so angle 4 is definitely 90. angles 3 and 5 would be 45 because it's an isosceles right triangle meaning that 1 angle is 90 and that the total of the other two angles would be 90 as a triangle angle sum is 180 and since it's isosceles just divide 90 by 2 because the 2 angles are the same getting 45for angles 3 and 5.
13. the triangle includes 2 exterior angles so...360 divided by 8 = 45 (this is the measure of each exterior angle of the polygon)
45 x 2 cause as I said it includes 2 exterior angles to get 90. it's a triangle so 180 (the sum of angles in triangle) minus 90 to get 90. so 1 and 2 are both 45 and 3 is 90
1-D, 2-C, 3-A, 4-C, 5-B, 6-A, 7-D, 8-B
Rise is 3 and run is 1 so the slope is 3
Answer:
y= 2/3x +1
Step-by-step explanation:
The y intercept is 1 It crosses the y axis at 1. So the point is (0,1)
Another point on the line is (3,3)
We can calculate the slope
m = (y2-y1)/(x2-x1)
= (3-1)/(3-0)
=2/3
The equation for a line is y=mx+b where m is the slope and b is the y intercept
y= 2/3x +1
