<span>a= 2 ft/s^2
t=3 s
vi=4 ft/s
vf=?
One can use the kinematic equation: vf=vi+at
vf=(4 ft/s)+(2 ft/s^2)(3 s)= (4 ft/s)+(6 ft/s)=10 ft/s</span>
Answer:
d, To undo addition, you can use multiplication
Step-by-step explanation:
a, To remove a whole number next to the variable, multiply both sides by that number
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
the answer is (6, -4)
Step-by-step explanation:
Do you mean 7 more than the product of 5 and a number? If so the answer is... y=7+5x
