The equation of the least-squared regression line is: In(Element) = 2.305 - 0.101(Time).
<h3>What is a regression line?</h3>
A regression line displays the connection between scattered data points in any set. It shows the relation between the dependent y variable and independent x variables when there is a linear pattern.
According to the given problem,
From the table we can see,
ln(Element) is the dependent variable and Time is the independent variable.
The constant = 2.305,
Time = -0.101
Hence, we can conclude, our least squared regression line will be
In (Element) = 2.305 - 0.101 (Time).
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Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
Answer:
I’m sorry I don’t know
Step-by-step explanation:
Answer:
y = –7x – 11
6x – 4y = 10
Step-by-step explanation:
From the question given above, we obtained:
x = –1
y = –4
y = ?x – 11 ....... (1)
6x – ?y = 10b......... (2)
Let the two unknown be a and b. Thus the above equation becomes:
y = ax – 11 ......... (3)
6x – by = 10 .......(4)
Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:
For a:
y = ax – 11
x = –1
y = –4
–4 = a(–1) – 11
–4 = –a – 11
Collect like terms
–4 + 11 = –a
7 = –a
Multiply through by –1
a = –7
For b:
6x – by = 10
x = –1
y = –4
6(–1) – b(–4) = 10
–6 + 4b = 10
Collect like terms
4b = 10 + 6
4b = 16
Divide both side by 4
b = 16 / 4
b = 4
Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.
y = ax – 11
a = –7
y = –7x – 11
6x – by = 10
b = 4
6x – 4y = 10
Therefore, the complete equation are:
y = –7x – 11
6x – 4y = 10
