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Roman55 [17]
2 years ago
14

verline%7B8%20-%202%7D%29%20%5C%7D%5D%20%5C%5C%20" id="TexFormula1" title=" Simplify: \: 18 \div 16 + [8 \{16 \div (10 - \overline{8 - 2}) \}] \\ " alt=" Simplify: \: 18 \div 16 + [8 \{16 \div (10 - \overline{8 - 2}) \}] \\ " align="absmiddle" class="latex-formula">
Correct Explanation will be mark as brainliest.​
Mathematics
2 answers:
german2 years ago
6 0

Step-by-step explanation:

The answer is 33.125.

Hope this helps

tester [92]2 years ago
3 0
<h3><u>Simplify :</u></h3>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}

<u>Simplifying vinculum bar </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}

<u>Simplifying parentheses brackets</u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}

<u>Simplifying curly brackets </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \dfrac{16}{4} \bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \cancel{\dfrac{16}{4}} \bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}

<u>Simplifying square brackets </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + 32}}}}

<u>According to BODMAS rule simplifying devision </u>

{:\implies{\small{\sf{18 \div 16 + 32}}}}

{:\implies{\small{\sf{ \dfrac{18}{16}  + 32}}}}

{:\implies{\small{\sf{{\cancel{\dfrac{18}{16}}  + 32}}}}}

{:\implies{\small{\sf{ 1.125 + 32}}}}

<u>Now, according to BODMAS rule simplifying addition</u>

{:\implies{\small{\sf{ 1.125 + 32}}}}

{:\implies{\small{\sf{33.125}}}}

{:\implies{\underline{\boxed{\pmb{\sf{Answer = 33.125}}}}}}

<u>∴ The answer is 33.125.</u>

<u>\underline{\rule{200pt}{2.5pt}}</u>

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