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BaLLatris [955]
3 years ago
14

Given that point A is the midpoint of line segment ED, where E( -1,9) and A(4,5), what is the location of point D?

Mathematics
1 answer:
yuradex [85]3 years ago
8 0

Answer:

  D(9, 1)

Step-by-step explanation:

A being the midpoint means its coordinates satisfy ...

  A = (E + D)/2

Solving for D, we find ...

  D = 2A -E

  = 2(4, 5) -(-1, 9) = (2·4 +1, 2·5 -9)

  D = (9, 1)

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Write the nth term of the following sequence in terms of the first term of the sequence.
vovikov84 [41]

Givens

Sequence 2, - 4, 8, -16, 32 ....

First term = a = 2

Problem

Find the nth term

tn = (-1 )^(n -1) * (a)^n answer or

tn = (-1)^(n - 1) * 2^n

where a is defined as the first term (it usually is given that designation).

Try a few to make sure the formula is correct

<em>n = 1</em>

t1 = (-1)^(1 - 1) * 2^1

t1 = (-1)^0 * 2

t1 = 1 * 2 = 2

<em>n =2</em>

t2 = (-1)^(2 - 1) * 2^2 = (-1)^1 * 4 = -4

6 0
3 years ago
PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi
Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

Hypotenuse^2=Base^2+Perpendicular^2

⇒ 5^2=3^2+4^2

Let a, b, c forms a Pythagorean triplet

a^2+b^2=c^2

Multiplied by 4 on both sides

⇒ 4a^2+4b^2=4c^2

⇒ {2a}^2+{2b}^2={2c}^2

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

4 0
3 years ago
Read 2 more answers
Why might Razis method not be a good way to estimate the probability? My team won 18 of their last 20 matches, so the probabilit
FrozenT [24]

Answer:

It is a really idealistic way to estimate probability.

It usually works well for random events where there is no restriction like:

"There are N elements in a set, the probability of randomly selecting any element is the same (so there is no restriction) meaning that for every single element, the probability is 1/N.

Now suppose that there are K elements (K < N) with a given characteristic, then the probability of randomly selecting one of the K elements out of the sett with N elements is equal to K times the probability of each element, this is:

P = K*(1/N) = K/N"

Then if a dice has 6 possible outputs, and we want to find the probability of getting a 3 or a 5, we need to find the quotient between the outcomes where we get a 3 or a 5 (2) and the total number of outcomes (6)

P = 2/6

Now let's go to the case in the problem:

We know that out of the last 20 games, your team won 18.

Then yes, your team won (18/20)*100% = 90% of their played games.

Does this mean tath the probability of winning the next game is 90%?

Well no, because this is not a random selection, there are a lot of other things needed to analyze, as the win rate of the other team (suppose that the other team won 14 of their last 20 games, then their win rate is (16/20)*100% = 70%

Does this mean that the probability where our team wins is 90%, and the probability of the enemy team winning is 70%?

Well no, this makes no sense at all, and this is why this method is not a good way to estimate probability in complex cases like this one.

5 0
3 years ago
Help me!! Which statement is correct?
Natasha2012 [34]

Answer:

D option is correct

( At Q3 the market is wasting society's .. )

3 0
3 years ago
A car averages 16.8 miles per gallon and uses 265 gallons traveling cross-country. What was the distance the car traveled
Norma-Jean [14]

1 gallon = 16.8 miles

265 gallons = 16.8 x 265 = 4452 miles


Answer: 4452 miles

8 0
3 years ago
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