<span>let:
m1 = 2xy a
m2 = 2xy b
m3 = 2x2y c
since 2 and 3 have a common factor let b=2n
m1 = 2xy a
m2 = 2xy 2 n
m3 = 2x2y c
or simply
m1 = 2xy a
m2 = 2xy 2n
m3 = 2xy 2c
given that anc have no common factors</span>
Answer:
Step-by-step explanation:
Area of sector = angle/360 * pi * r^2
7.1 = 40/360 * 22/7 * r^2
7.1 = 1/9 * 22/7 * r^2
63.9 = 22r^2/7
r^2 = (7 * 63.9)/22
r^2 = 20.331818181818
r = square root of 20.331818181818
r = 4.51
d = r * 2 = 4.51 * 2 = 9.02
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
