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3 years ago

11

use the formula d=rt to find the distance traveled by a car driving at an average speed of 50 miles per hour for four and a half

hours

2 answers:

Mama L [17]3 years ago

7 0

As per problem, we have

Average speed of car =50 miles per hour.

Time = $4\frac{1}{2} hr$

Given formula to use is

$d=rt$

$\text{where d=distance traveled, r=Average speed, t= time}\\$

So, to find the distance traveled can be find by substituting the values in the above equation we get

$d=50*4\frac{1}{2}\\\\d=50*\frac{9}{2}\\\\d=25*9\\\\d=225 \ miles\\$

Hence distance traveled =225 miles.

Mumz [18]3 years ago

6 0

Since she goes 50 mph for 4 and a half hours, we multiply 50 by 4 1/2

50 * 4 1/2 = 225

She travels 225 miles. Hope this helps!

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What is the solution to the quadratic equation 8m^2+7m-15=-7 ?

Aleks04 [339]

Make equal to zero
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quadratic fomrula

if you have
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3 years ago

What is the value of x in the following equation: 5=25+x?

diamong [38]

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3 years ago

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Hunter-Best [27]

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3 years ago

Read 2 more answers

One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W

Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P( $\text{B}_1$ ) = 0.2, P( $\text{B}_2$ ) = 0.4, P( $\text{B}_3$ ) = 0.3, P( $\text{B}_4$ ) = 0.6, P( $\text{B}_5$ ) = 0.5.

So, the probability that the cell will be killed is given by;

P(A)= $1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]$

P(A) = $1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]$

P(A) = $1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)$

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

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3 years ago

Consider the equation x^2=36 which of the statements below are true

pentagon [3]

Given:

the equation x^2 = 36

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To determine the roots of the equation, solve:

x^2 = 36

x = +6
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3 years ago