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pav-90 [236]
3 years ago
15

Lourdes plans to jog at least 1.5 miles. Write and solve an inequality to find x, the number of hours that Lourdes will have to

jog..
Mathematics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

An inequality compares two or more variables by using the <, >, ≤, or ≥ signs.

The number of hours Lourdes will have to jog is 0.4 hours

From the given parameters:

Lourdes plans to jog for at least a distance of 1.5 miles

If Lourdes can jog averagely at the speed of 3.75 mph

Then,

the inequality that can represent the information can be written as:

= 1.5 miles ≤ 3.75 (x) miles/hour

Solving the inequality;

= 1.5 ≤ 3.75 (x)

Making (x) the subject of the formula, we have:

x =  0.4 hours

Therefore, we can conclude that the number of  hours lourdes will have to jog is 0.4 hours

Step-by-step explanation:

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The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses.
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Using the z-distribution, it is found that the 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

If we had increased the confidence level, the margin of error also would have increased.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

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  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96. Increasing the confidence level, z also increases, hence the margin of error also would have increased.

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n = 450, \pi = 0.47.

The lower and the upper bound of the interval are given, respectively, by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.4239

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The 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

More can be learned about the z-distribution at brainly.com/question/25890103

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