Answer:
the rate of change of the water depth when the water depth is 10 ft is; 
Step-by-step explanation:
Given that:
the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.
We are meant to find the rate of change of the water depth when the water depth is 10 ft.
The diagrammatic expression below clearly interprets the question.
From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t
Then the similar triangles ΔOCD and ΔOAB is as follows:
( similar triangle property)


h = 2.5r

The volume of the water in the tank is represented by the equation:



The rate of change of the water depth is :

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec
Then,

Therefore,

the rate of change of the water at depth h = 10 ft is:




Thus, the rate of change of the water depth when the water depth is 10 ft is; 
Answer: -1/2, -0.22, 0, 12%, 0.56
Step-by-step explanation:
-1/2 is equal to -0.50, making it the number with the least value.
-0.22 is closer to 0 than -0.50, meaning it is greater then -0.50 and less than 0.
0 is between the negative and positive numbers, giving it the spot that it has.
12% is equivalent to 0.12, meaning it is more than 0, and less than 0.56, which is the greatest number.
0.56 has more value than any other number in the problem, meaning it goes last in the order.
Two lines are parallel if they intersect.
7000*.03*6=?? Step 1. multiply 7000*.03=210 Step 2. multiply 210*6=1260. the answer is $1,260.00
The airplane is 48 feet long in real dimensions.
To find out how long the airplane actually is, we can use the scale and input our amount of inches that it is measured by.
So, 1 inch equals to 6 feet.
Our model plane is 8 inches.
Now, we plug it in.
8 inches = 6(8)
8 inches = 48 feet
Therefore, the length of the real airplane is 48 feet.
48 feet