<span>A
and B must be invertible, we have UA=B, since A is invertible. A^-1 exists, by multiplying with A^-1,
we have UA A^-1 =B A^-1. But AA^-1 = I (identity matrix)
and XI=X, for all matrix X, we find UI= B A^-1, and U= B A^-1.</span>
Answer:
11x + 10y - 2w
Step-by-step explanation:
Hello!
To solve for the perimeter, we add up the like terms.
What are like terms?
Like terms are terms with the same variable and degree. 4x and 5y are NOT like terms because the variable is not the same. However, 4x and 3x are like terms, as adding them gives us 7x.
4x and 4x² are not like terms, because the degree of 4x is 1 (degree means the largest exponent), but the degree of 4x² is 2.
Solve for Perimeter:
Combine the like terms by adding them up.
- Perimeter = (8x - 4w) + (3y + 2w) + (3x + 7y)
- P = 8x - 4w + 3y + 2w + 3x + 7y
- P = 8x + 3x + 3y + 7y - 4w + 2w
- P = 11x + 10y - 2w
The perimeter is 11x + 10y - 2w
2x + 1.5x +20 = 90
3.5 x = 90-20
3.5 x = 70
x = 70/3.5
x = 20
angle DAE = 2*20 = 40
angle CAD = 1.5*20 +20 = 50
21-6=15
The range of the set is 15
