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3 years ago

13

Simplified radical form of 4800 feet how many seconds was the diver in a free fall? Using functions (t)=16t^2 models the distanc

e s (t), in feet , that an object falls in t seconds.

1 answer:

amm18123 years ago

5 0

Answer:

The diver will be in free fall for $10\sqrt{3}$ seconds.

Step-by-step explanation:

The distance in feet, that an object falls in t seconds is given by the function $h(t) = 16t^{2}$ .

Now, given that the height is 4800 feet and we have to calculate the number of seconds the diver was in a free fall.

Therefore, $4800 = 16t^{2}$

⇒ $t^{2} = \frac{4800}{16} = 300$

⇒ $t = \sqrt{300} = \sqrt{100 \times 3} = 10\sqrt{3}$ seconds.

Therefore, the diver will be in free fall for $10\sqrt{3}$ seconds. (Answer)

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19 Kayla's car can hold 15 gallons of gas. She gets 20.5 miles per gallon The tank is full. About how far can Kayla drive if she

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Answer:

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Step-by-step explanation:

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2 years ago

Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?

natima [27]

Answer:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

Step-by-step explanation:

The question is poorly formatted. The original question is:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

We have:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

Open bracket

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 8 as 2^3

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 2^3 as 8

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}$

Expand each exponent

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}$

Split

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}$

Factorize

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

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2 years ago

Read 2 more answers

Write an equation of the line shown. Then use the equation to find the value of x when y=112

PtichkaEL [24]

Answer:

$y = 8x + 16$

$x = 12$

Step-by-step explanation:

Given two points on the line (0, 16) and (3, 40), an equation for the line can be written using the slope-intercept line equation which takes the format $y = mx + b$ .

Where,

$m = slope = \frac{y_2 - y_1}{x_2 - x_1}$

b = y-intercept or the point at which the line cuts the y-axis.

Let's find slope (m) using the slope formula:

Let,

$(0, 16) = (x_1, y_1)$

$(3, 40) = (x_2, y_2)$

$slope (m) = \frac{40 - 16}{3 - 0}$

$slope (m) = \frac{24}{3}$

$slope (m) = 8$

Find b. Substitute the values of x = 0, y = 16, and m = 8 in the slope-intercept formula to find b.

$y = mx + b$

$16 = 8(0) + b$

$16 = 0 + b$

$16 = b$

$b = 16$

Plug in the values of m and b into the slope-intercept formula to get the equation of the line.

$y = mx + b$

$y = 8x + 16$

Let's use the equation to find x when y = 112.

$y = 8x + 16$

Substitute y = 112 in the equation

$112 = 8x + 16$

$112 - 16 = 8x$

$96 = 8x$

Divide both sides by 8

$12 = x$

$x = 12$

8 0

2 years ago

5. Firewood is often sold by the cord. A cord of wood is a bundle measuring 4 feet by 4 feet by 8 feet. What's the volume of a c

Eduardwww [97]

V = L * W * H
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2 years ago

F(x)= -1/3x+13 when value is f(-3)

almond37 [142]

Answer:

14

Step-by-step explanation:

f(x)=-1/3x+13

f(-3)=-1/3(-3)+13

f(-3)=3/3+13

f(-3)=1+13

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1 year ago