Question

Simplified radical form of 4800 feet how many seconds was the diver in a free fall? Using functions (t)=16t^2 models the distance s (t), in feet , that an object falls in t seconds.

Answer 1

Answer:

The diver will be in free fall for $10\sqrt{3}$ seconds.

Step-by-step explanation:

The distance in feet, that an object falls in t seconds is given by the function $h(t) = 16t^{2}$.

Now, given that the height is 4800 feet and we have to calculate the number of seconds the diver was in a free fall.

Therefore, $4800 = 16t^{2}$

⇒ $t^{2} = \frac{4800}{16} = 300$

⇒ $t = \sqrt{300} = \sqrt{100 \times 3} = 10\sqrt{3}$ seconds.

Therefore, the diver will be in free fall for $10\sqrt{3}$ seconds. (Answer)