CosΘ < 0 ->2nd or 3rd quadrant
cotΘ > 0 -> 1/tanΘ > 0 -> tanΘ >0 -> 1st and 3rd quadrant.
So Θ lines in the 3rd quadrant
1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!
2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!
I hope this helped! Brainliest? :) -Raven❤️
Answer:
Step-by-step explanation:
11x-3+5x-9=180
16x-12=180
16x=192
x=12
<pst=129
Answer:
f^-1 (x) = 1+ln( (x-3)/2)
Step-by-step explanation:
hello :
let f(x) = y so : y = 2e^(x-1) +3
calculate x : e^(x-1) = (y-3)/2
for : y-3 > 0 : x-1 = ln( (y-3)/2) so : x= 1+ln( (y-3)/2)
If(x)= 2e^(x-1) +3 , what is f^-1 (x) = 1+ln( (x-3)/2)
