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Allisa [31]
2 years ago
6

4x−4y=-2 and −9x−4y ​ =-3 solve by adding please !!!

Mathematics
1 answer:
jeyben [28]2 years ago
7 0
1. Add 4x back into -2, you now have -4y=-4x-2. Add +4 from y and now you are at y=-4x+2 and this is the answer!

2. Add -9x back into -3, you now have -4y=9x-3. Add +4 from y and now you are at y=9x-7 and this is your answer!!

I hope this helped! Brainliest? :) -Raven❤️
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if there are 20 vakues in a data set in order from smallest to largest what is the median of the data set
Bumek [7]
To find the median of 20 values, list the values from smallest to largest then add the 10th and 11th number then divide by 2 and you get your median.
5 0
3 years ago
Simplify (3s^8)^-5 write your answer using only positive exponents. help please!!
loris [4]

Answer:

1 / ( 243s^40 )

Step-by-step explanation:

For this problem, we need to know that a negative exponent simply can be rewritten in the opposing part of the fraction, for this case, the denominator.  So we can simplify as shown:

(3s^8)^-5

= 1 / (3s^8)^5

= 1 / 3^5 * s^8^5

= 1 / 243 * s^40

= 1 / ( 243s^40 )

Cheers.

3 0
2 years ago
2×2=<br><img src="https://tex.z-dn.net/?f=2%20%2B%202%20%3D%20" id="TexFormula1" title="2 + 2 = " alt="2 + 2 = " align="absmiddl
alisha [4.7K]

Answer:

they both equal 4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help............​
Xelga [282]

Answer:

2x+14

Step-by-step explanation:

(3/4)x-7.3+(5/4)x+21.3

(3/4+5/4)x+21.3-7.3

2x+14

4 0
2 years ago
A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po
Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call h the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is h - 49.

The wire length d is 14 ft longer than height h, hence

d= h+14.

Thus we get a right triangle with hypotenuse d= y+14, perpendicular  h, and base h-49; therefore, the Pythagorean theorem gives

(h-49)^2+h^2 = (h+14)^2

which upon expanding we get:

h^2-98h+2401 = h^2+28h+196

further simplification gives

h^2-126h+2205=0,

which is a quadratic equation with solutions

h =21ft\\h = 105ft.

Since the first solution h =21ft will give the triangle base length of 21ft-49ft = -28ft which is negative; therefore, we disregard it and pick the solution h = 105ft.

Hence, the height of the pole is 105ft.

3 0
2 years ago
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