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Mashutka [201]
3 years ago
15

Solve the equation for x: 3(m+7)=6(m+2)

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0

Answer:

3

Step-by-step explanation:

There is no x in the equation, so I will assume solving for m

Distribute:

3m + 21 = 6m + 12

Subtract 3m and 12

3m = 9

Divide by 3

m = 3

erastova [34]3 years ago
5 0
3=m

Distribute 3 to (m+7) and distribute 6 to (m+2)
With that you end up with:
3m + 21 = 6m + 12
Subtract 3m from 6m
21=3m+12
Then subtract 12 from 21
9=3m
Divide by 3 in both sides
3=m
And that’s your answer!
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Check the following pair of linear equations is consistent or inconsistent
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Answer:

Consistent

Step-by-step explanation:

It was a solution.

8 0
3 years ago
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Find the missing factor.<br> n(n-3)+2(n-3)=( )(n-3)
elena-s [515]
This is the concept of quadratic equations. We are required to find the missing factor in the partially factored quadratic equation given;
n(n-3)+2(n-3)=()(n-3)
here we proceed as follows;
n(n-3)+2(n-3)
when we factor this we get:
(n-3)(n+2)
this can be written as:
(n+2)(n-3)
The answer is (n+2)
3 0
3 years ago
If it starts out at -10 degrees, what will the temperature be if it rises 30 degrees?
Bond [772]

add 30 to -10:

-10 + 30 = 20

 Answer is B.

4 0
4 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
Determine if the finite correction factor should be used. If​ so, use it in your calculations when you find the probability. In
serg [7]

Answer:

Idk

Step-by-step explanation:

5 0
3 years ago
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