The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
Answer:
1 meter.
Step-by-step explanation:
1 1/2 * 1/3
= 3/2 * 1/3
= 3/6
= 1/2.
So John used 2*1/2 = 1 meter of the ribbon.
Answer: Equilateral triangles.
Explanation: We know that in similar polygons, its all the corresponding angles are congruent. Only the set of equilateral triangles contains members that are always similar( by AAA similarity criteria) to one another as the measure of all the angles of equilateral triangle is fixed i.e. 60°.
Rest other do not have fixed measure for angles in it.
Answer:
The grade for path a is 257.1428571%
The grade for path b is 213.5%
Step-by-step explanation:
To find the grade of a slope, you take the rise over run then you multiply by 100.
