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solniwko [45]
3 years ago
5

Solve the equation 6×+2(2×-3)=18

Mathematics
2 answers:
andrew-mc [135]3 years ago
5 0

Answer:

x= 2.4

hope this help you out

Natalka [10]3 years ago
3 0

Answer:

x=\frac{12}{5}

x=2.4

Step-by-step explanation:

6x+2\left(2x-3\right)=18

<u>Expand 2(2x-3) by applying Distributive law:</u>

<u />2\times \:2x-2\times \:3

Multiply:

2\times \:2x=4

2\times \:3=6

4x-6

6x+4x-6=18

<u>Combine like terms:</u>

6x+4x=10x

10x-6=18

<u>Add 2 to both sides:</u>

10x-6+6=18+6

10x=24

<u>Divide both sides by 10:</u>

\frac{10x}{10}=\frac{24}{10}

x=\frac{12}{5}

_____________________

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Urn 1 contains 3 blue tokens and 2 red tokens; urn 2 contains 2 blue tokens and 4 red tokens. All tokens are indistinguishable.
Dmitry_Shevchenko [17]

Answer:

RR = 0.4

RB = 0.3

BB = 0.22

BR = 0.30

Step-by-step explanation:

P( Urn 1 ) = 2/6 = 1/3

P( Urn 2 ) = 1 - 1/3 = 2/3

Urn 1 contains : 3 blue and 2 red

P( blue | urn 1 ) = 3/5 ( with replacement ) , P( blue | urn 1 ) = 3/4 ( without replacement )

P( red | urn 1 ) = 2 / 5 ( with replacement ) , P(red | urn 1 ) = 1/2 ( without replacement )

Urn 2 contains : 2 blue and 4 red

P ( blue | urn 2 ) = 1/3 ( with replacement ) , P( blue | urn 2 ) = 2/5 ( without replacement )

P ( red | urn 2 ) = 2/3 ( with replacement) , P( red | urn 2 ) = 4/5 ( without replacement )

Determine

<u>i) Possible outcomes when two tokens are drawn from either Urn without replacement </u>

RR = [[ ( 2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] = 0.4

RB = [[ (2/5 * 1/3 ) + ( 2/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.3

BB = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 3/4 *1/3 ) + ( 2/5 * 2/3 ) ]] ≈ 0.22

BR = [[ ( 3/5 * 1/3 ) + ( 1/3 * 2/3 ) ] * [ ( 1/2 * 1/3 ) + ( 4/5 * 2/3 ) ]] ≈ 0.30

<u />

8 0
3 years ago
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