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Vikentia [17]
3 years ago
9

Find the Mean, Median, Mode & Range. If possible, round to the nearest tenth. 3, 8, 7, 2, 4, 8, 3, 4​

Mathematics
2 answers:
Masja [62]3 years ago
5 0

Answer:

Mean- 4.9

Median- 4

Mode- 3,4,8

Range- 6

Step-by-step explanation:

The mean of a sequence is the average amount. This is equal to all of the terms' sum divided by the number of terms. So, to find the mean add 2+3+3+4+4+7+8+8, which equals 39. Then, divide by 8 because that is the number of terms. Therefore, the mean is 4.9.

The median is the number in the middle of the sequence. To find the median order the sequence from least to greatest and find the middlemost number. In this case, that is 4.

The mode is the number that appears most often. In this sequence, 3, 4, and 8 all appear twice.

The range is the difference between the minimum and maximum. So, subtract 2 from 8 to get 6.

viktelen [127]3 years ago
3 0

Answer:

Mean: 4.875

Median: 4

Mode: 3, 8, 4

Range: 6

the last part i don’t know

Step-by-step explanation:

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Emma is counting by sixes what # will she say
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Write the equation of a line with a slope of 2/3 going through the point (-15, -22)
Assoli18 [71]

Answer:

y=(2/3)(x+15)-22

Step-by-step explanation:

You use the slope point equation which is y-y1=m(x-x1) or y=m(x-x1)+y1 where m is the slope and x1 and y1 are the coordinates you plug in.

Therefore, 2/3 is the slope m and (-15, -22) are the coordinates for x1 and y1.

y=(2/3)(x-(-15)) + (-22)

y=(2/3)(x+15)-22

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3 years ago
You jog 3.6 miles in 30 minutes. At that rate, how long will it take you to jog 4.8 miles?
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Answer:

40 minutes

Step-by-step explanation:

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6 0
3 years ago
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Given b (x) = StartAbsoluteValue x + 4 EndAbsoluteValue, what is b (negative 10)?
Vlada [557]
Plug in –10 into |x+4|.

b(–10) = |-10+4|
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4 0
3 years ago
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A random sample of 30 males with online dating profiles are recruited for a study about lying in online dating profiles. Each ma
laiz [17]

Answer:

The 95% confidence interval for the difference in mean profile height and mean actual height of online daters is between 0.27 and 0.87 inches.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 30 - 1 = 29

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0452

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0452\frac{0.81}{\sqrt{30}} = 0.3

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.57 - 0.3 = 0.27 inches.

The upper end of the interval is the sample mean added to M. So it is 0.57 + 0.3 = 0.87 inches.

The 95% confidence interval for the difference in mean profile height and mean actual height of online daters is between 0.27 and 0.87 inches.

3 0
3 years ago
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