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3 years ago

X^(2)+x^(2)=128 or x^2+x^2=128

Mathematics

2 answers:

LenaWriter [7]3 years ago

7 0

Answer:

8 =6 since 8 squared is 64 and 64 +64 or 64 times 2 is 128 that’s is your answer.

Step-by-step explanation:

Dvinal [7]3 years ago

4 0

Answer:

Step-by-step explanation:

x^2 + x^2 = 128 Normally you don't do this but rewrite the question

1x^2 + 1x^2 = 128

You actually do use 1 + 1 = 2 First time I've ever done that.

2x^2 = 128 Divide by 2

2x^2/2 = 128 / 2

x^2 = 64 Take the square root of both sides

sqrt(x^2)= sqrt(64)

x = 8

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Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

$q(a) = {a}^{2} + 3a + 4$

Multiply sides by -2 :

$- 2q(a) = - 2( {a}^{2} + 3a + 4)$

$- 2q(a) = - 2 {a}^{2} - 6a - 8$

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Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

$q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\$

$q(a + 1) = {a}^{2} + 2a + 1 + 3a + 3 + 4 \\$

$q(a + 1) = {a}^{2} + 5a + 8$

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Step (3)

$q(a + 1) - 2q(a) =$

${a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 = \\$

$- {a}^{2} - a = - a(a + 1)$

And we're done.

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8 0

4 years ago

Help please 10 points

xxTIMURxx [149]

Answer:

Step-by-step explanation:

tell me the question ?? did not say the question ok ??

8 0

3 years ago

What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

Lena [83]

To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2

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3 years ago

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sp2606 [1]

Answer:

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Step-by-step explanation:

a. 2i + 6j + 3i + 7j = 5i + 13j

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