3 years ago

PLEASE ANSWER THIS I WILL GIVE YOU 7 POINTS

Mathematics

1 answer:

MissTica3 years ago

6 0

Answer:

tell me the question

Step-by-step explanation:

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brilliants [131]

D) as age increases, weight increases by 5

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B5%7D%20%29%20%7B%7D%5E%7Bx%7D%20%3D%20125" id="TexFormula1" title="( \f

anzhelika [568]

Well we know that... $a^{-1}=\frac{1}{a^{1} }\\$ .

So... $(\frac{1}{5})^{-1}=\frac{1}{\frac{1}{5}^{1}}=5\\\\$ .

Because $5^{3}=125$ ,

$\frac{1}{5}^{-1*3}=125\\ x=-1*3=-3$

answer: -3

8 0

3 years ago

Ted is making a rectangular frame out of wood. The wood costs $1.25 per foot. The sides of the triangle are in a ratio of 4:3:2.

Oliga [24]

How are you making a rectangular frame but it needs to be a triangle?

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3 years ago

Read 2 more answers

At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years

Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,

When interest is compound Annually:

$Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

3 0

3 years ago

Find A when p= 2000, r= 7%, n= 4, and t= 4

I am Lyosha [343]

A=prt

A=2000×7%×4

=560

3 0

2 years ago