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Mekhanik [1.2K]
3 years ago
10

Importance of folders on a computer ​

Computers and Technology
1 answer:
Darya [45]3 years ago
5 0

Answer: to keep everything organised

Explanation:

If we never had folders then we wouldnt be able to find our important documents and then we would have folders so its all organised in differen catogries so we can access them easire

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You browsing internet and you realize that its not responding what do you do with out rebooting the computer
Allisa [31]
You can try and turn wifi off then on press save on whatever you were doing if you can then reboot it. other then that theres not many more options.
4 0
3 years ago
5.17 (Calculating Sales) An online retailer sells five products whose retail prices are as follows: Product 1, $2.98; product 2,
Dima020 [189]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    //Initialize the prices as constants

    final double PRODUCT_1_PRICE = 2.98;

    final double PRODUCT_2_PRICE = 4.50;

    final double PRODUCT_3_PRICE = 9.98;

    final double PRODUCT_4_PRICE = 4.49;

    final double PRODUCT_5_PRICE = 6.87;

   

    //Declare the other variables

    int productNumber, quantitySold;

    double total = 0.0;

   

    //Create a Scanner object to get input

    Scanner input = new Scanner(System.in);

   

    //Create a while loop

    while(true){

        //Ask the user to enter the productNumber

     System.out.print("Enter the product number or 999 to quit: ");

     productNumber = input.nextInt();

     

     // Stop the loop, if productNumber is 999(sentinel value, you may choose any value you want)

     if(productNumber == 999)

         break;

     

     //Ask the user to enter the quantitySold

     System.out.print("Enter the quantity sold: ");

     quantitySold = input.nextInt();

     

     //Create a switch statement that works depending on the productNumber entered.

     //For example, if the productNumber is 1, it multiplies the quantitySold by PRODUCT_1_PRICE

     //   and adds the result to the total. If productNumber is 2, it does the same for product 2 ...

     switch(productNumber){

         case 1:

             total += quantitySold * PRODUCT_1_PRICE;

             break;

         case 2:

             total += quantitySold * PRODUCT_2_PRICE;

             break;

         case 3:

             total += quantitySold * PRODUCT_3_PRICE;

             break;

         case 4:

             total += quantitySold * PRODUCT_4_PRICE;

             break;

         case 5:

             total += quantitySold * PRODUCT_5_PRICE;

             break;

     }

    }

 

 //Print the total (when the loop is done)

 System.out.println("The total is $" + total);

}

}

Explanation:

*The code is in Java.

You may see the explanation as comments in the code.

4 0
3 years ago
How are < embed > tags used in web page creation?
yKpoI14uk [10]

Answer:

The <embed> HTML element embeds external content at the specified point in the document. This content is provided by an external application or other source of interactive content such as a browser plug-in.

Explanation:

7 0
2 years ago
Consider a pipelined processor with just one level of cache. assume that in the absence of memory delays, the baseline cpi of th
babunello [35]

Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.

8 0
2 years ago
When cleaning a computer, you need only worry about what you can see.
almond37 [142]

Answer:

False because the inside could be dirty and cause problems.

Explanation:

4 0
2 years ago
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