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Leno4ka [110]
3 years ago
14

Which of the following is irrational?

Mathematics
2 answers:
fgiga [73]3 years ago
7 0
It’s D because it is
CaHeK987 [17]3 years ago
6 0

D becuase if you square root 11 you get an irrational number try putting it in the calculator and you would get a crazy number

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Will give brainliest
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Answer:

7.1

Step-by-step explanation:

If you count how many units are between the library and the park, it is seven units.

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Is 0.343434 an irrational or rational?
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irrational

Step-by-step explanation:

a rational number is always a whole number

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Adam is carrying books to the classroom for his teacher. Each books weighs 3.85 pounds. If he carries 4 books, how many pounds i
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Adam is carrying 15.4 pounds because 3.85*4=15.4
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Which number is not a member of the solution set of the inequality 4x ≥ 18
lapo4ka [179]

Answer:

4.4

Step-by-step explanation:

4 (4.4) ≥ 18 does not make sense. 4 x 4.4 = 17.6, which is not more than or equal to 18.

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3 years ago
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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
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