when searching for a peer-reviewed journal article, you see the phrase "full text available" in the item record. what does this
1 answer:
You might be interested in
Answer:
Step by step code along with explanation and output is given below
Explanation:
We can solve this problem using if elif else approach
def main():
# prompts the user to enter an integer from 1 to 10
num = int (input('Enter a number in the range of 1 to 10:\n'))
# using the if elif print out the roman numeral from 1 to 10
if num == 1:
print ('Roman Numeral for 1 is I')
elif num == 2:
print ('Roman Numeral for 2 is II')
elif num == 3:
print ('Roman Numeral for 3 is III')
elif num == 4:
print ('Roman Numeral for 4 is IV')
elif num == 5:
print ('Roman Numeral for 5 is V')
elif num == 6:
print ('Roman Numeral for 6 is VI')
elif num == 7:
print ('Roman Numeral for 7 is VII')
elif num == 8:
print ('Roman Numeral for 8 is VIII')
elif num == 9:
print ('Roman Numeral for 9 is IX')
elif num == 10:
print ('Roman Numeral for 10 is X')
# using the else print out error message whenever user enters any other number not listed above
else:
print ('Error! Wrong Input')
# call the main function
main()
Output:
Enter a number in the range of 1 to 10:
6
Roman Numeral for 6 is VI
Enter a number in the range of 1 to 10:
15
Error! Wrong Input
Answer:
Explanation:
The code does not fail on the first step since 1900 divided by 4 is actually 475 and has no remainder, meaning that it should return True. The code won't work because the if statements need to be nested in a different format. The correct algorithm would be the following, which can also be seen in the picture attached below that if we input 1900 it would output is not a leap year as it fails on the division by 400 which gives a remainder of 0.75
input_year = int(input())
if input_year % 4 == 0:
if input_year % 100 == 0:
if input_year % 400 == 0:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
else:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
