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2 years ago

14

Can you help me please.

2 answers:

SVEN [57.7K]2 years ago

5 0

Answer:

can you take a better photo?

amm18122 years ago

3 0

Step-by-step explanation:

Full view of the picture please

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What is minimal completion time for the activities in the graph below? In a complete sentence, explain how you got your answer

kupik [55]

The minimal completion time for the activities is the shortest possible time for all the activities to be finished. In doing this, we look at the path that would require the greatest amount of time. At the START node, we choose the path that would take the longest which is 7 days leading to ACTIVITY D. Next, we choose the path leading to ACTIVITY B which takes 5 days. Then, we move to ACTIVITY C taking 5 days and finally, reach the END which would take 6 days. So, the minimal completion time is:
7 + 5 + 5 + 6 = 23 days

6 0

3 years ago

PPPPPPPPlease help me (20 points!!!!)

Vika [28.1K]

$\longrightarrow{\mathfrak{\frac{-9}{6}÷\frac{3}{-2}}}$

$\longrightarrow{\sf{\frac{-\cancel{9}}{\cancel{6}}\times\frac{-\cancel{2}}{\cancel{3}}}}$

$\longrightarrow{\sf{\frac{3}{3}}}$

$\longrightarrow{\boxed{\bf{1}}}$

Identity applied -

$\star{\:\:\:\:\:\:\boxed{\bf{\frac{a}{b}÷\frac{c}{d}=\frac{a}{b}\times\frac{d}{c}}}}$

4 0

3 years ago

Find the slope between the pair of points (1,3) and (7,2)

agasfer [191]

Answer:

$\bold{m=-\dfrac16}$

Step-by-step explanation:

$\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}$

(1, 3) ⇒ x₁ = 1, y₁ = 3

(7, 2) ⇒ x₂ = 7, y₂ = 2

So the slope:

$\bold{m=\dfrac{2-3}{7-1}=\dfrac{-1}6=-\dfrac16}$

5 0

3 years ago

Evaluate the expression 4x^4 y^3 when x=1/5 and y=6

wariber [46]

Answer:

5.5296

Step-by-step explanation:

to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6

4x^4 y^3

4 × x^4 × 4× y³

4 × (1/5)∧4 × 4 × 6³

4× (0.2)∧4 × 4 × 216

4 × 0.0016 × 864

0.0064 × 864

5.5296

5 0

3 years ago

The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse

diamong [38]

Answer: The answer is cosine of that acute angle.

Step-by-step explanation: We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

$\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.$

Thus, the ratio is cosine of the acute angle.

7 0

3 years ago