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harkovskaia [24]
3 years ago
5

A circle has a radius of (6x+11) centimeters. Which statement is true?

Mathematics
2 answers:
PolarNik [594]3 years ago
6 0

If a circle has a radius of (6x + 11), it is true that: <u>D. The </u><u>circumference </u><u>of the </u><u>circle </u><u>is </u>(12x + 22) \pi $ cm<u />

<em><u>Recall the following about a </u></em><em><u>circle</u></em><em><u>:</u></em>

  • Area of a circle = \pi r^2
  • Circumference of a circle = 2 \pi r

If a circle has a radius of (6x+11) $ cm, the area and circumference of the circle would be the following:

  • Area of a circle =  \pi r^2

  • Substitute  r = (6x+11) into the area formula

\pi (6x + 11)^2

  • Expand

\pi \times (6x + 11) \times (6x + 11)\\\\\pi \times(36x^2 + 66x + 66x + 121)\\\\\pi \times  (36x^2 + 132x + 121)\\\\ area = (36x^2 + 132x + 121) \pi $ cm^2

  • Circumference of a circle = 2 \pi r

  • Substitute  r = (6x+11) into the circumference formula

2 \times \pi \times  (6x + 11)\\\\Circumference = (12x + 22) \pi

Therefore, if a circle has a radius of (6x + 11), it is true that: <u>D. The </u><u>circumference </u><u>of the </u><u>circle </u><u>is </u>(12x + 22) \pi $ cm<u />

Learn more here:

brainly.com/question/14772815

marin [14]3 years ago
3 0

Answer:

D.The circumference of the circle is (12x+22)π centimeters.

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The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
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Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

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