You would divide 245 by 49 to get a
a= 5
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer:
Hello,
Please, see the attached file.
Thanks.
Step-by-step explanation:
Answer:
The answer is -4
Step-by-step explanation:
-2x-6<=1
-2(-4)-6<=1
8-6<=1
2<=1 which is False
-2x-6<=1
-2(-3)-6<=1
6-6<=1
0<=1 which is True
-2x-6<=1
-2(-2)-6<=1
4-6<=1
-2<=1 which is True
-2x-6<=1
-2(-1)-6<=1
2-6<=1
-4<=1 which is True