You could have half a cookie, divide it into thirds. (a semi circle cut into thirds)
Let x denote the length of the side of the garden which is covered fenced by a shed, and

be the width of the garden.
The perimeter of a rectangle is given by 2(length + width)
i.e.
which gives:

For the area to be maximum, the differentiation of A with respect to x must be equal to 0.
i.e.

Therefore, the maximum area of the garden enclosed is given by
Answer:
7
Step-by-step explanation:
(x-2)^2
x^2-4x+4
-3^2-4(-3)+4=7
58.4 rad. The clock shows up to 12. Divide 360/12 to get degrees per 5 mins. Then multiply it by five and convert to rad
Answer: (a) 9
Step-by-step explanation:
We are given that ,
The first two classes of a frequency distribution are 0-9 and 10-19.
We know that the class width of an class interval is basically the difference between the upper limit and the lower limit of the interval.
For example the class interval for interval 40 - 45 is 5 because 45-40=5.
For the given class interval 0-9 , upper limit= 9
Lower limit =0
⇒ Class width = 9-0= 9
Similarly , for 10-19 , the class width = 19-10=9
Therefore , the class width is 9 .
Hence, the correct answer is (a) 9.