What is a possible step when solving for x? select all that apply

Area of a circle is directly proportional to the square of radius of the circle while the circumference is proportional to the radius of the circle. This means that if the radius of a circle is increased x times, then its area will be increased to x^2 times the original area, and the circumference will increase to x times the original circumference.

Thus when the radius is doubled, or in other words if radius mad 2 time the original radius, the area of circle will become 2^2 = 4 time the original area. The circumference will become 2 times the original circumference.

We can calculate exact area and circumference of a circle from its radius using the following equations:

Area of circle = (pi/4)*r^2

Circumference of circle = 2*pi*r

Where r is the radius of the circle.

I know this is a lot, sorry.

3 0

3 years ago

heyy soo i just started math class and im veryy confused I've tried different things to get to the answer but it didn't work soo

german

yes sure, i learned this before so

1. a. make a proportion here, of percentage. $\frac{225}{250} =\frac{x}{100}$ if you cross multiply and divide you get 90%.

1. b. obviously the empty seats would be 10%.

2. a. proportion again, $\frac{0.90}{6.00} =\frac{x}{100}$ cross multiply then divide you ge 15%

3. 30% in decimal form is 0.3. multiply it then to the total amount, so 0.3 x 15 = 4.5

7 0

3 years ago

Read 2 more answers

4)In order to set rates, an insurance company is trying to estimate the number of sick daysthat full time workers at an auto rep

bagirrra123 [75]

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.92}{2} = 0.04$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.04 = 0.96$ , so Z = 1.88.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that $\sigma = 2.2$

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1 = 1.88\frac{2.2}{\sqrt{n}}$

$\sqrt{n} = 1.88*2.2$

$(\sqrt{n})^2 = (1.88*2.2)^2$

$n = 17.1$

Rounding up:

A sample of 18 is required.

3 0

2 years ago