Eric plans to rent a room for his graduation party for $400. The catering charge is $9.50 per person

Enzo is making a scale drawing of the rectangle below.

Nitella [24]

Answer:

Enzo is not correct because he did not multiply the length and width by the same factor.

I do not think Enzo is not correct because he did not multiply the length and width by the same factor.

he is making a drawing of the rectangle below.

A rectangle has a length of 8 centimeters and width of 5 centimeters.

Suppose a new rectangle will have the length of 16 cm.

Enzo says that he can draw an enlarged rectangle that is 16 centimeters by 13 centimeters. Enzo is not correct because he did not multiply the length and width by the same factor.

4 0

4 years ago

If 4m-7n=10 and 2m+2n=4, what is the value of 2m-9n?

Ipatiy [6.2K]

4m - 7n = 10
2m + 2n = 4 - multiply everything by -1.

4m - 7n = 10
-2m - 2n = -4 Add the 2 equations

(4m - 7n = 10)
+(-2m - 2n = -4)
-------------------------
2m - 9 n = 6.

The value of 2m - 9n would be 6.

3 0

4 years ago

Three of the sides will require fencing and the fourth wall already exists. If the farmer has 116 feet of fencing, what are the

dolphi86 [110]

Answer:

29 ft x 58 ft

Step-by-step explanation:

Let x be the length of each side perpendicular to the wall, and y be the length of the side parallel to the wall.

The amount of wire available is:

$116 = 2x+y\\y=116-2x$

The area of the region is:

$A=xy=x(116-2x)\\A(x)=116x-2x^2$

The value of 'x' for which the derivate of the area function is zero will yield the maximum area:

$A(x)=116x-2x^2\\A'(x) = 116-4x=0\\x=29\ ft$

The value of y is:

$y=116-2*29\\y=58\ ft$

The dimensions of the region with the largest area are 29 ft x 58 ft.

7 0

3 years ago

1.What would be the points of AA'B'C' after AABC was reflected across the y-axis? A (-4,1) B (4,3) C (0,-1) 2. What would be the

Schach [20]

Answer:

B its a guess because nothing is shown

Step-by-step explanation:

6 0

3 years ago

Explain the steps to finding the vertex of g(x) = 3x2 + 12x + 15

RUDIKE [14]

Answer:

The vertex of this parabola, $(-2, 3)$ , can be found by completing the square.

Step-by-step explanation:

The goal is to express this parabola in its vertex form:

$g(x) = a\, (x - h)^2 + k$ ,

where $a$ , $h$ , and $k$ are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at $(h,\, k)$ .

The vertex form can be expanded to obtain:

$\begin{aligned}g(x)&= a\, (x - h)^2 + k \\ &= a\, \left(x^2 - 2\, x\, h + h^2\right) + k = a\, x^2 - 2\, a\, h\, x + \left(a\,h^2 + k\right)\end{aligned}$ .

Compare that expression with the given equation of this parabola. The constant term, the coefficient for $x$ , and the coefficient for $x^2$ should all match accordingly. That is:

$\left\lbrace\begin{aligned}& a = 3 \\ & -2\,a\, h = 12 \\& a\, h^2 + k = 15\end{aligned}\right.$ .

The first equation implies that $a$ is equal to $3$ . Hence, replace the " $a\!$ " in the second equation with $3\!$ to eliminate $\! a$ :

$(-2\times 3)\, h = 12$ .

$h = -2$ .

Similarly, replace the " $a$ " and the " $h$ " in the third equation with $3$ and $(-2)$ , respectively:

$3 \times (-2)^2 + k = 15$ .

$k = 3$ .

Therefore, $g(x) = 3\, x^2 + 12\, x + 15$ would be equivalent to $g(x) = 3\, (x - (-2))^2 + 3$ . The vertex of this parabola would thus be:

$\begin{aligned}&(-2, \, 3)\\ &\phantom{(}\uparrow \phantom{,\,} \uparrow \phantom{)} \\ &\phantom{(}\; h \phantom{,\,} \;\;k\end{aligned}$ .

8 0

3 years ago