P^8 • p^−3 • p^2<span>=<span><span>p^10/</span><span>p^3</span></span></span><span>=<span>p7
</span></span>
So y=mx+b
m=slope
y=-3x+b
subsitutue 1 for x and 4 for y
4=-3(1)+b
4=-3+b
add 3 to both sides
7=b
the equaiton is y=-3x+7
The surface area of a right cylinder is the sum of the areas of the lateral face and the circular bases. The lateral face is really just a rectangle with the same height as the cylinder and a length equal to the circumference of the circular base.
If the radius of the base is

and the height is

, then the surface area of the cylinder is

You're given that the area is

and the radius is

, so you have
Answer:
Part 1) The base is
and the height is
Part 2) The base is
and the height is
Step-by-step explanation:
case 1) Right isosceles triangle of the left
Let
x------> the base of the rectangle
y----> the height of the rectangle
Remember that
In a right isosceles triangle the lengths of the legs of the triangle is the same

----> equation A

-----> equation B
substitute equation B in the equation A



Find the value of x
case 2) Right isosceles triangle of the right
Let
x------> the base of the rectangle
y----> the height of the rectangle
Remember that
In a right isosceles triangle the lengths of the legs of the triangle is the same

----> equation A

-----> equation B
substitute equation B in the equation A



Find the value of y