All categories

3 years ago

I rlly need help with thins question asap

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:

2 miles; 10 miles

Step-by-step explanation:

For a distance of 3,520 yards...

3,520 = 1,760m

Divide both side by 1,760

m = 2 miles

For a distance of 17,600 yards...

17,600 = 1,760m

Divide both sides by 1,760

m = 10 miles

Gnesinka [82]3 years ago

5 0

Answer:

The 3 one is 2 and the forth one is 10

Step-by-step explanation:

i did the math

You might be interested in

o paint a house, two painters are hired. The first painter can paint the entire house in ten hours. The second painter will need

alexandr1967 [171]

11+6=17 17÷2= 8.5 hours so the answer would be 4:50pm. Maybe

7 0

3 years ago

19. During a 2 3/4 hour assembly, each speaker spoke for 1/4 of an hour. How many speakers were there?

atroni [7]

Answer:

11 speakers

Step-by-step explanation:

2 3/4 ÷ 1/4

11/4 ÷ 1/4

11/4 x 4/1 = 44/4 = 11

6 0

3 years ago

Read 2 more answers

A manager records the repair cost for 4 randomly selected stereos. A sample mean of $82.64 and standard deviation of $14.32 are

zysi [14]

Answer:

CI = (70.861 , 94.418)

Step-by-step explanation:

In order to determine the 90% confidence interval you use the following formula (for a population approximately normal):

$CI=(\overline{x}-Z_{\alpha/2}\frac{\sigma}{\sqrt{n}},\overline{x}+Z_{\alpha/2}\frac{\sigma}{\sqrt{n}})$ (1)

$\overline{x}$ : mean = 82.64

σ: standard deviation = 14.32

n: sample = 4

α: tail area = 1 - 0.9 = 0.1

Z_α/2 = Z_0.05: Z factor = 1.645

You replace these values and you obtain:

$Z_{0.05}(\frac{14.32}{\sqrt{4}})=(1.645)(\frac{14.32}{\sqrt{4}})=11.778$

The confidence interval will be:

$CI=(82.64-11.778,82.64+11.778)=(70.861,94.418)$

The 90% confidence interval is (70.861 , 94.418)

6 0

3 years ago

A yoga membership costs $16 and an additional $7 per class. write a linear equation modeling the cost of a yoga membership.

MrRissso [65]

Y=16x+7
the x represents the number of memberships the 16 represents the cost of a membership and the 7 represents the additional cost.

8 0

4 years ago

Read 2 more answers

Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).

ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

$\overrightarrow {PQ}==$

$\overrightarrow {PR}==$

The nonzero vector orthogonal to the plane through the points P,Q, and R is

$\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}$

$\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}$

Expand along row 1.

$\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}$

$\overrightarrow n=i(-9)-j(8)+k(2)$

$\overrightarrow n=-9i-8j+2k$

$\overrightarrow n=$

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0

3 years ago

I rlly need help with thins question asap​

I rlly need help with thins question asap