Let's see which of these best measures the data.
The mean is the average, or the sum of all numbers divided by the total numbers there are.
4.8 + 3 + 2.7 + 4.4 + 4.8 + 9.9 = 29.6
There are 6 numbers total.
29.6/6 = 4.93.
The mean is 4.93.
Let's try our median. The median is the middle number of a sequence listed from least to greatest. I will make the list for you.
2.7, 3, 4.4, 4.8, 4.8, 9.9.
Cross out the smallest number with the greatest number.
3, 4.4, 4.8, 4.8.
4.4, 4.8.
Since we do not have a middle number, we must see what number is in the middle of 4.4, and 4.8. To determine this, we must average. Add 4.4 and 4.8, then divide by 2.
9.2/2 = 4.6.
4.6 is our median.
The mode is the number that appears the most, so let's find the number that is the most frequent.
4.8 is our mode.
The best number that will fit in this to make it work out is 4.6.
The median is your answer, B.)
I hope this helps!
Answer:
1. c 2. a 3. b
Step-by-step explanation:
The best way to prove these results are the right ones is by multiplying diagonally :
1. 1/3 = 4/12 -----> 1 . 12 = 12 ; 3 . 4 =12
2. 1/2 = 3/6 ------> 1 . 6 = 6 ; 2 . 3 = 6
3. 2/5 = 6/15 -----> 2 . 15 = 30 ; 5 . 6 = 30
The results of the multiplications must be the same if the fractions are equivalent.
The top right is the answer. The base should be square with lengths of 8 and the height is 10.
Answer:
rfhrdhdrhrhdrhrhr
Step-by-step explanation:
Answer: (f·g)(x) = -5x³ - 31x² + 62x + 18
(f·g)(-1) = -70
(fog)(x) = 25x² - 130x + 155
(fog)(-1) = 310
<u>Step-by-step explanation:</u>
f(x) = x² + 8x + 2 g(x) = -5x + 9
(f·g)(x) = (x² + 8x + 2)(-5x + 9)
= -5x³ + 9x²
- 40x² + 72x
<u> - 10x + 18</u>
= -5x³ - 31x² + 62x + 18
(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18
= -5(-1) - 31(1) - 62 + 18
= 5 - 31 - 62 + 18
= -70
****************************************************************************************
(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2
= 25x² - 90x + 81
- 40x + 72
<u> + 2</u>
= 25x² - 130x + 155
(fog)(-1) = 25(-1)² - 130(-1) + 155
= 25 + 130 + 155
= 310
<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>
