All categories

2 years ago

Answerrrr plzzzzzzzzzzzzz

Mathematics

2 answers:

Andrew [12]2 years ago

8 0

Answer:

33 big man

Step-by-step explanation:

i need brainliest plzz

Burka [1]2 years ago

6 0

Answer: 33

Explanation:

1) Subtract 5 from both sides of the equation

4+5=137

4x+5=137

4+5−5=137−5

2)Simply

Subtract the numbers

Divide by 4

4=132

Cancel terms that are in both the numerator and denominator

Divide the numbers

=33

Solution

=33

You might be interested in

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

Which expressions are less than 610

Lady bird [3.3K]

Answer:

Step-by-step explanation:

7 0

3 years ago

Hello I need help with my homework if someone could help me and explain to me how this works that would be great thank you

Tatiana [17]

Answer:

Step-by-step explanation:

5. 17.25-8.25= 9

6. 7+8=15

7. 2*8=16 or 2*9=18

7 0

3 years ago

Read 2 more answers

Reason Lena is making a puzzle, she cuts a shape into5. two pieces and rearranges them to make the shape below.Which shape did s

BartSMP [9]

The answer to 5. is D: the square

4 0

3 years ago

Read 2 more answers

Think About a Plan Write an indirect proof.

Alekssandra [29.7K]

1) Either $\ell \parallel p$ or $\ell$ ∦ $p$ (only two possibilities)

2) Assume $\ell \parallel p$ (one of two possibilities)

3) $\angle 1 \cong \angle 2$ (if two parallel lines are cut by a transversal, the corresponding angles are congruent)

4) But $\angle 1$ is not congruent to $\angle 2$ (given)

5) So $\ell$ ∦ $p$ (only other possibility)

8 0

2 years ago