If the area of the larger circle is 25 times the area of the smaller circle then the radius of the larger circle is how many tim
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The answer is 
![\sqrt[3]{ \frac{ a^{6} b^{9} }{-64} } = \frac{ \sqrt[3]{a^{6} b^{9}} }{ \sqrt[3]{-64} } = \frac{ \sqrt[3]{a^{6}} * \sqrt[3]{ b^{9}} }{ \sqrt[3]{-64}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B%20a%5E%7B6%7D%20b%5E%7B9%7D%20%20%7D%7B-64%7D%20%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Ba%5E%7B6%7D%20b%5E%7B9%7D%7D%20%7D%7B%20%20%5Csqrt%5B3%5D%7B-64%7D%20%20%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Ba%5E%7B6%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B%20b%5E%7B9%7D%7D%20%7D%7B%20%20%5Csqrt%5B3%5D%7B-64%7D%7D%20)
Since (xᵃ)ᵇ = xᵃ*ᵇ, then:
a⁶ = (a²)³
b⁹ = (b³)³
Also: 64 = 4³
![\frac{ \sqrt[3]{a^{6}} * \sqrt[3]{ b^{9}} }{ \sqrt[3]{-64}}= \frac{ \sqrt[3]{( a^{2})^{3} }*\sqrt[3]{( b^{3})^{3} } }{\sqrt[3]{( -4)^{3} }} = \frac{ a^{2} * b^{3} }{-4}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Csqrt%5B3%5D%7Ba%5E%7B6%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B%20b%5E%7B9%7D%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B-64%7D%7D%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B%28%20a%5E%7B2%7D%29%5E%7B3%7D%20%7D%2A%5Csqrt%5B3%5D%7B%28%20b%5E%7B3%7D%29%5E%7B3%7D%20%7D%20%7D%7B%5Csqrt%5B3%5D%7B%28%20-4%29%5E%7B3%7D%20%7D%7D%20%3D%20%5Cfrac%7B%20a%5E%7B2%7D%20%2A%20b%5E%7B3%7D%20%7D%7B-4%7D%20)
Since (xᵃ)ᵇ = xᵃ*ᵇ, then:
a⁶ = (a²)³
b⁹ = (b³)³
Also: 64 = 4³