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Aliun [14]
3 years ago
6

150 is what % off 250

Mathematics
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

60%

Step-by-step explanation:

Hope this helps!

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Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.
rodikova [14]

Answer:

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x)^2 = x^2

121 + 121^2 - 121(2)x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not

7 0
3 years ago
PLS HELP DUE IN 1 HOUR WILL GIVE BRAINLIEST 5 STARS AND A THANKSSSS
Assoli18 [71]

Answer:

x=5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(5x²+2) - (-4x²+7)+(-3x²-5)
svp [43]

Answer:

6x^2   -10

Step-by-step explanation:

(5x²+2) - (-4x²+7)+(-3x²-5)

Distribute the minus sign

(5x²+2) +4x²-7 +(-3x²-5)

Combine like terms

5x²+4x²-3x²  +2-7-5

6x^2              -10

6 0
4 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
4 years ago
(13p5 + 6p - 12p2) - (-9p - p2 - 13p5)
anastassius [24]

Answer:

Step-by-step explanation:

13p⁵ + 6p - 12p² -(-9p - p² - 13p⁵) = 13p⁵ + 6p - 12p² + 9p + p² + 13p⁵

{Distribute  (-1) to the second expression}

= <u>13p⁵ + 13p⁵</u>    <u>-12p² + p²</u>     <u>+ 6p + 9p</u>

{Combine like terms}

= 26p⁵ - 11p² + 15p

7 0
3 years ago
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