Answer:
1.8m^2 approx
Step-by-step explanation:
Given data
P1= 1400N
A1=0.5m^2
P2=5000 N
A2=??
Let us apply the formula to calculate the Area A2
P1/A1= P2/A2
substitute
1400/0.5= 5000/A2
cross multiply
1400*A2= 5000*0.5
1400*A2= 2500
A2= 2500/1400
A2= 1.78
Hence the Area is 1.8m^2 approx
Answer:
A, 12:47
Step-by-step explanation:
14.7 mm is the height.
Use the volume equation for a cylinder which is
volume=(PI/4)*(diameter^2)*(height)
And you have volume, and diameter (which is just radius times 2) so solve for height.
5588=(PI/4)*(22^2)*Height
Height = 14.7 mm
Answer: A
Step-by-step explanation:
Since multiplication is the only operation under the radical, you can apply the root to each term. Im not sure if I worded that correctly, but ill hopefully explain correctly.
First we need to take the cubed root of 648. This number doesn't have a perfect root, but it can be simplified. 648 is the same as 216*3, and 216 has a perfect cubed root of 6. So we can bring the 6 outside of the radical
![3x*6\sqrt[3]{3x^4y^8}=18x\sqrt[3]{3x^4y^8}](https://tex.z-dn.net/?f=3x%2A6%5Csqrt%5B3%5D%7B3x%5E4y%5E8%7D%3D18x%5Csqrt%5B3%5D%7B3x%5E4y%5E8%7D)
The next step is simplifying the variables, which is the easiest part. Just split them up into multiples of 3, again poor explanation but Ill show what I mean.
![18x\sqrt[3]{3x^3xy^3y^3y^2}](https://tex.z-dn.net/?f=18x%5Csqrt%5B3%5D%7B3x%5E3xy%5E3y%5E3y%5E2%7D)
The cubed root and the cubed power will cancel and can be brought outside the radical![18x*xy^2\sqrt[3]{2xy^2} =18x^2y^2\sqrt[3]{3xy^2}](https://tex.z-dn.net/?f=18x%2Axy%5E2%5Csqrt%5B3%5D%7B2xy%5E2%7D%20%3D18x%5E2y%5E2%5Csqrt%5B3%5D%7B3xy%5E2%7D)