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MAVERICK [17]
3 years ago
14

Evaluate the expression ab2 + 2ab + a2 for a = 6 and b = 3.

Mathematics
2 answers:
natta225 [31]3 years ago
8 0

Answer:

b) 126

Step-by-step explanation:

ab^2 + 2ab + a^2 (I assume this is what you meant)

(6)(3)^2 + 2(6)(3) + (6)^2

Simplify.

126

Aliun [14]3 years ago
6 0

Answer:

I believe there is an error with the problem

Step-by-step explanation:

3*6*2 + 2*6*3 + 6*2 = 36+36+12 = 84

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Step-by-step explanation

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Step-by-step explanation:

It might be 21/30 , hope it helps though :)

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If Jerry bought the stock at the face value, it means that the stock is now below its face value, and that is said that the stock is below par.

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A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
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Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

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3 years ago
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