How do you ordered pair that represents a solutions to the system of linear inequalities below?

A point is a ______.

yanalaym [24]

The answer can be A B C or D

6 0

4 years ago

Read 2 more answers

Plz help

ratelena [41]

Answer:

radius by 2 ye this will be the correct answer d=r/2

3 0

3 years ago

The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va

Lemur [1.5K]

Answer:

The mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

The probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

The probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

Step-by-step explanation:

Let X = total taxable earnings of workers.

The expected value of the random variable X is:

E (X) = μ = $28.29

The standard deviation of the random variable X is:

SD (X) = σ = $33.493.

The data was collected from 56 American counties.

The sample mean of a random variable is the an unbiased estimator of the population mean.

If repeated samples are collected from a population and the mean for each sample is computed then the expected value of the sample means is same as the population mean.

So the mean total taxable earnings of all wage earners in a county is same as the population mean, $28.29.

According to the Central limit theorem if we have a population with mean μ and standard deviation σ and take appropriately huge random-samples (n ≥ 30) from the population with replacement, then the distribution of the sample-means will be approximately normally distributed.

Then, the mean of the sample means is given by, $\mu_{\bar x}=\mu$ .

And the standard deviation of sample means is, $\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Compute the value of P (\bar X < 33) as follows:

$P(\bar X$

Thus, the probability that the mean taxable wages in James' sample of 56 counties will be less than $33 million is 0.8508.

Compute the value of P (\bar X > 30) as follows:

$P(\bar X>30)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{30-28.29}{33.943/\sqrt{56}})\\=P(Z>0.38)\\=1-P(Z$

Thus, the probability that the mean taxable wages in James' sample of 56 counties will be greater than $30 million is 0.3520.

5 0

3 years ago

A manufacturer claims that the batteries it makes will last 18 hours, with a standard deviation of 1.5 hours. If the durations o

mel-nik [20]

Answer:

B. 0.0918

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 18, \sigma = 1.5$