How do you ordered pair that represents a solutions to the system of linear inequalities below?
1 answer:
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Equation
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x² + 4x = 0
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Add a constant
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x² + 4x + (4/2)² - (4/2)² = 0 ← Add 2² to form perfect square
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Evaluate bracket
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x² + 4x + 2² - 2² = 0
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Form the perfect square
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(x + 2)² = 4
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Square root both sides
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(x+2) =
√4
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Evaluate the square root
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(x+2) = 2
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Solve x
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x = 2 - 2 or x = -2 - 2
x = 0 or -4
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Answer: The constant to add is 4 and the value of x = 0 or -4
------------------------------------------------------------------
Equation
------------------------------------------------------------------
x² + 4x = 0
------------------------------------------------------------------
Add a constant
------------------------------------------------------------------
x² + 4x + (4/2)² - (4/2)² = 0 ← Add 2² to form perfect square
------------------------------------------------------------------
Evaluate bracket
------------------------------------------------------------------
x² + 4x + 2² - 2² = 0
------------------------------------------------------------------
Form the perfect square
------------------------------------------------------------------
(x + 2)² = 4
------------------------------------------------------------------
Square root both sides
------------------------------------------------------------------
(x+2) =
------------------------------------------------------------------
Evaluate the square root
------------------------------------------------------------------
(x+2) =
------------------------------------------------------------------
Solve x
------------------------------------------------------------------
x = 2 - 2 or x = -2 - 2
x = 0 or -4
------------------------------------------------------------------
Answer: The constant to add is 4 and the value of x = 0 or -4
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