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Feliz [49]
2 years ago
6

M=1/2(d1+d2) (solve for d1)

Mathematics
2 answers:
nekit [7.7K]2 years ago
7 0

Answer:

d1= -d2+M

Step-by-step explanation:

you would multiply d1 and d2 by 1/2, then add negative d2/2 to each side, then divide each side by 2/1.

hope it helps

mark me brainliest pls

cricket20 [7]2 years ago
6 0

Answer:

d=\frac{2M}{3}

Step-by-step explanation:

Switch sides

\frac{1}{2}\left(d\cdot \:1+d\cdot \:2\right)=M

Multiply both sides by 2 to remove the fraction

2\cdot \frac{1}{2}\left(d\cdot \:1+d\cdot \:2\right)=2M

Then simplify

3d=2M

  • Divide both sides by 3

\frac{3d}{3}=\frac{2M}{3}

d=\frac{2M}{3}

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3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
During the winter clearance sale, The Cyclery has marked down all bicycles
strojnjashka [21]

Answer:

During the winter clearance sale, The Cyclery has marked down all bicycles

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Step-by-step explanation:

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3 years ago
Bailey sold pumpkin pies for two days. on Monday, she sold 13 pies and on Tuesday she sold 23 pies. If she used 3/4 cup of pumpk
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
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To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
3 years ago
Read 2 more answers
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