Answer:
The rate of change of the tracking angle is 0.05599 rad/sec
Step-by-step explanation:
Here the ship is traveling at 15 mi/hr north east and
Port to Radar station = 2 miles
Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles
Therefore the ship, port and radar makes a triangle with sides
2, 7.5 and x
The value of x is gotten from cosine rule as follows
x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04
x = 6.25 miles
By sine rule we have

Therefore,

α = Angle between radar and ship α
∴ α = 58.052
Where we put
to get
and differentiate to get
= 3.208 degrees/second = 0.05599 rad/sec.
Applying the linear angles theorem, the measures of the larger angles are: 130 degrees.
The measures of the smaller angles are 50 degrees
<h3>How to Apply the Linear Angles Theorem?</h3>
Based on the linear angles theorem, we have the following equation which we will use to find the value of y:
3y + 11 + 10y = 180
Add like terms
13y + 11 = 180
Subtract 11 from both sides
13y + 11 - 11 = 180 - 11
13y = 169
13y/13 = 169/13
y = 13
Plug in the value of y
3y + 11 = 3(13) + 11 = 50 degrees
10y = 10(13) = 130 degrees.
Therefore, applying the linear angles theorem, the measures of the larger angles are: 130 degrees.
The measures of the smaller angles are 50 degrees.
Learn more about the linear angles theorem on:
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Answer:
After solve the equations we get value of k=3
Step-by-step explanation:
We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.
If the lines are concurrent, they pass through same point.
Let:

First solving equation 1 and 2 to find values of x and y
From eq(1) we find value of x and put it in eq(2)

After solving we get value of y=-1
Now putting in eq(1) to get value of x

So, Value of x= 2
Now put value of x=2 and y=-1 into eq(3) to find value of k

So, After solve the equations we get value of k=3