Label each statement as TRUE or FALSE.

Two students in different classes took the same math test. Both students received a

ivann1987 [24]

Answer:

Both students scored in the top 10% of their classes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Top 10% = Above the 100 - 10 = 90th percentile.

The 90th percentile of scores is X when Z has a pvalue of 0.9, that is, Z = 1.28.

So, the student who had a z-score above 1.28 scored in the 90th percentile of their class.

In student A's class the mean was 78 and the standard deviation of 5. He scored 87.

We have that $\mu = 78, \sigma = 5, X = 87$

Then

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{87 - 78}{5}$

$Z = 1.8$

1.8 > 1.28, so student A scored in the top 10% of his/her class.

Student B's class the mean was 76 with a standard deviation of 4. Scored 87.

We have that $\mu = 76, \sigma = 4, X = 87$

Then

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{87 - 76}{4}$

$Z = 2.75$

2.75 > 1.28, so student B also scored in the top 10% of his/her class.

Both students scored in the top 10% of their classes.

8 0

3 years ago

2+d=2-3(d-5)-2 Pls show work

defon

2 + d = 2 - 3(d- 5) - 2

First, cancel 2 on both sides. / Your problem should look like: $d = -3(d - 5) - 2$
Second, expand. / Your problem should look like: $d = -3d + 15 - 2$
Third, simplify -3d + 15 - 2 to get -3d + 13. / Your problem should look like: $d = -3d + 13$
Fourth, add 3d to both sides. / Your problem should look like: $d + 3d = 13$
Fifth, add d + 3d to get 4d. / Your problem should look like: $4d = 13$
Sixth, divide both sides by 4. / Your problem should look like: $d = \frac{13}{4}$

Answer as fraction: $d = \frac{13}{4}$
Answer as decimal: $d = 3.25$

3 0

4 years ago

Read 2 more answers

Please help!!

Allushta [10]

We know that

AB = 10x + 4

BC = 4x - 3

AC = 12x + 16

We need to find x, AB and BC.

The solution of the question is based on the assumption that the point A, B and C are col-linear, i.e. they lie on the same line, and B lies between A and C

⇒ AB + BC = AC

Substituting the values of AB, BC and AC in terms of x in the above equation, and solving the linear equation.

⇒ 10x+4 + 4x-3 = 12x+16

⇒ 14x+1 = 12x+16

⇒ 2x = 15

⇒ x = 7.5

Substituting the value of x in 10x+4 to determine the length of AB

AB = 10x+4

⇒ AB = (10×7.5)+4

⇒ AB = 75+4

⇒ AB = 79

Hence, AB is 79 units

Substituting the value of x in 4x-3 to determine the length of BC

BC = 4x-3

⇒ BC = (4×7.5)-3

⇒ BC = 30-3

⇒ BC = 27

Hence, BC is 27 units

4 0

4 years ago

You buy lunch for gas at a party. You can spend no more than $100. You will spend $20 on beverages and $10 per guest and sandwic

azamat

70$ used

i hop dis helps

3 0

3 years ago

Someone pls help me????

ch4aika [34]

10 is 16.7% of 60.

10/60 = 1/6

1/6 = 16.7%

8 0

4 years ago