From the information given;
1 bag of concrete = 1000 in^3
2 bags at home = 1000*2 = 2000 in^3
The available space has a volume of;
Volume = (5*12)*10*10 (Note: 1 ft = 12 inches)
Volume = 60*10*10 = 6000 in^3
The remaining volume = Available space - occupied space = 6000 - 2000 = 4000 in^2
1 bag = 1000 in^3
x bags = 4000 in^2
Then,
x = 1*4000/1000 = 4 bags.
This means 4 more bags of concrete will be required to fully fill the space.
Answer: You find midpoint by adding the two x values together and dividing by 2, then adding the two y values together and dividing by two.
x/5 = 6/15
15x = 30
x = 2
answer
x = 2 ft
y/10 = 6/15
15y = 60
y = 4
answer
y = 4 ft
Answer:
1080
Step-by-step explanation:
PEMDAS says multiply and divide from left to right
9*5*6*3÷3*4*6÷6
45*6*3÷3*4*6÷6
270*3÷3*4*6÷6
810÷3*4*6÷6
270*4*6÷6
1080*6÷6
6480÷6
1080
Answer:
The frequency distribution is given below:
Class Frequency
0 - 9 9
10 - 19 6
20 - 29 3
30 - 39 3
40 - 49 3
From the given 4 options, the histogram in option A accurately displays this data. Hence the option A is correct.
