I need help with number 3, i’m stuck!

How to solve subtracting rational coefficients

yuradex [85]

Step-by-step explanation:

There are a few steps to follow when you add or subtract rational expressions with unlike denominators.

To add or subtract rational expressions with unlike denominators, first find the LCM of the denominator. The LCM of the denominators of fraction or rational expressions is also called least common denominator , or LCD.

Write each expression using the LCD. Make sure each term has the LCD as its denominator.

Add or subtract the numerators.

Simplify as needed.

5 0

2 years ago

1. Classify the following polynomials as monomial, binomial trinomial and polynomial: <br> i) 2x + y

chubhunter [2.5K]

Answer:

binomial

Step-by-step explanation:

a monomial has 1 term

a binomial has 2 terms

a trinomial has 3 terms

2x + y has 2 terms and so is a binomial

6 0

2 years ago

Read 2 more answers

Which form most quickly reveals the vertex?

lana [24]

Answer:

first option

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

m(x) = - 2 (x - 6)² + 18 ← is in vertex form

with vertex = (6, 18 )

7 0

3 years ago

Read 2 more answers

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago

Y=2x-7<br> y=-3x+18 <br> solve by substitution

Liono4ka [1.6K]

Answer:

-x+11

Step-by-step explanation:

am not sure if this is correct but

2x-3x=-x

-7+18=11

-x+11

8 0

2 years ago