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irina [24]
3 years ago
8

I need help, the solid below is made from cubes find it volume

Mathematics
2 answers:
Vikki [24]3 years ago
7 0

Answer:

40cm

Step-by-step explanation:

Volume is LxWxH. The length is 2cm, the width is 5cm, and the height is 4cm, you can find these values by counting each block as a cm. Then you multiply all the values, (2x4x5) and you get 40.

Art [367]3 years ago
5 0

Answer:

[tex]\purple{\rule{45pt}{7pt}}\purple{\rule{45pt}{999999pt}}[tex]

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Help me now or else.
ivann1987 [24]

Answer: c. -3.8

Step-by-step explanation:

-9 1/5-10+2/5+2(14 1/2-70 simplifies to -46/5-10+2/5+2(29/2-7)

reduce numbers: -46/5-10+2/5+2x15/2

-46/5-10+2/5+15

-44/5+5= -19/5 = -3.8

7 0
3 years ago
5y - 25x =10 <br><br><br> I need someone to help me solve this asap
ruslelena [56]

Answer:slope=10.000/2.000=5.000

x-intercept=2/5=minus 0.40000

y-intercept=2/1=2.00000

Step-by-step explanation:

8 0
4 years ago
Find all zeros of x^4+x
Yuri [45]

Answer:

-1 and 0

Step-by-step explanation:

X ^4+x = 0;

x*(x^3+1)=0;

x*[(x^3-x)+(x+1)]=0;

x*[x(x-1)(x+1)+(x+1)]=0;

x*(x+1)(x^2-x+1)=0;

Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0

x=0 or -1

4 0
2 years ago
There is a number such that four times the number plus 3 is equal to 19. Find the number
frosja888 [35]

Answer:

4

Step-by-step explanation:

We have been given that it equals 19 when added to 3 and multiplied by 4 so follow these steps:

1. set the equation 4x+3=19

2. solve for x

4x+3-3=19-3

This is used to solve for x

3. 4x=16 is found

4. if 4x=16, we divide 16/4 and get 4!

That's your answer hope it helped!

3 0
4 years ago
Read 2 more answers
Responda: Por favor, é urgente.
kumpel [21]

Answer:

C) CA=40

Step-by-step explanation:

2y/(2y+4)=(2y+6)/4y

cross multiply

8y²=4y²+20y+24

4(2y²)=4(y²+5y+6)

divide both sides by 4

2y²=y²+5y+6

y²-5y-6=0

(y-6)(y+1)=0

So the answer must be either 6 or -1.  Since it can't be a negative number, it must be 6.

CA=2(6)+4+4(6)

CA=12+4+24

CA=40

5 0
3 years ago
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