Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
Hormones and water balance are another two conditions which are maintained by cells.
B) fetus
Hope this helps.
(Please mark this brainliest, I would really appreciate it) Thanks!
Everlasting cells are cells that are incapable of regeneration. these cells are taken into consideration to be terminally differentiated and non-proliferative in postnatal lifestyles. This includes neurons, heart cells, skeletal muscle cells, and pink blood cells.
Pink blood cells (RBCs) fall right into a truly less complicated category. Mature RBCs do not divide. In truth, because mature RBCs do not even have a nucleus, those cells in reality can not do an awful lot of anything other than act as vessels for the hemoglobin with which they are jam-packed. New RBCs are made in the marrow within the mature human.
Because the mitochondria are the mobile website for oxidative metabolism, where glucose is damaged all the way down to carbon dioxide and water to release energy, and because purple blood cells lack these organelles they cannot break down glucose absolutely aerobically.
Learn more about cells here:
brainly.com/question/13920046
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